(1/3)(x-6)=2

Solution for (1/3)(x-6)=2 equation:

(1/3)(x-6)=2

We move all terms to the left:

(1/3)(x-6)-(2)=0


Domain of the equation: 3)(x-6)!=0

x∈R


We add all the numbers together, and all the variables

(+1/3)(x-6)-2=0

We multiply parentheses ..

(+x^2+1/3*-6)-2=0

We multiply all the terms by the denominator


(+x^2+1-2*3*-6)=0

We get rid of parentheses

x^2+1-6-2*3*=0

We add all the numbers together, and all the variables

x^2=0

a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{2}=0$