(1/3)(y+3)+2=(1/6)(7y-55)-2

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Solution for (1/3)(y+3)+2=(1/6)(7y-55)-2 equation: 


y in (-oo:+oo)

(1/3)*(y+3)+2 = (1/6)*(7*y-55)-2 // - (1/6)*(7*y-55)-2

(1/3)*(y+3)-((1/6)*(7*y-55))+2+2 = 0

(1/3)*(y+3)+(-1/6)*(7*y-55)+2+2 = 0

1/3*(y+3)-1/6*(7*y-55)+2+2 = 0

1/3*(y+3)-1/6*(7*y-55)+2+2 = 0

2-5/6*y+2+61/6 = 0

2-5/6*y+73/6 = 0

85/6-5/6*y = 0

85/6-5/6*y = 0

85/6-5/6*y = 0 // - 85/6

-5/6*y = -85/6 // : -5/6

y = -85/6/(-5/6)

y = 17

y = 17

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