(1/3)(y-7)=2y+6

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Solution for (1/3)(y-7)=2y+6 equation: 


y in (-oo:+oo)

(1/3)*(y-7) = 2*y+6 // - 2*y+6

(1/3)*(y-7)-(2*y)-6 = 0

(1/3)*(y-7)-2*y-6 = 0

1/3*(y-7)-2*y-6 = 0

1/3*(y-7)-2*y-6 = 0

-5/3*y-6-7/3 = 0

-5/3*y-25/3 = 0

-5/3*y-25/3 = 0

-5/3*y-25/3 = 0 // + 25/3

-5/3*y = 25/3 // : -5/3

y = 25/3/(-5/3)

y = -5

y = -5

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