(1/3)(z+4)-6=(2/3)(5-z)

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Solution for (1/3)(z+4)-6=(2/3)(5-z) equation: 



(1/3)(z+4)-6=(2/3)(5-z)

We move all terms to the left:

(1/3)(z+4)-6-((2/3)(5-z))=0



Domain of the equation: 3)(z+4)!=0

z∈R





Domain of the equation: 3)(5-z))!=0

z∈R



We add all the numbers together, and all the variables

(+1/3)(z+4)-((+2/3)(-1z+5))-6=0

We multiply parentheses ..

(+z^2+1/3*4)-((+2/3)(-1z+5))-6=0

We calculate fractions


((+z^2+1*3)(-1z+5)))/36z^2+()/36z^2-6=0

We can not solve this equation

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