(1/3)*(3x+1)=1/2

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Solution for (1/3)*(3x+1)=1/2 equation: 


x in (-oo:+oo)

(1/3)*(3*x+1) = 1/2 // - 1/2

(1/3)*(3*x+1)-(1/2) = 0

(1/3)*(3*x+1)-1/2 = 0

1/3*(3*x+1)-1/2 = 0

(1/3*2*(3*x+1))/2-1/2 = 0

1/3*2*(3*x+1)-1 = 0

2*x-1/3 = 0

(2*x-1/3)/2 = 0

(2*x-1/3)/2 = 0 // * 2

2*x-1/3 = 0

2*x-1/3 = 0 // + 1/3

2*x = 1/3 // : 2

x = 1/3/2

x = 1/6

x = 1/6

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