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(1/3)-(1/12)=(1/x)
We move all terms to the left:
(1/3)-(1/12)-((1/x))=0
Domain of the equation: x))!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-((+1/x))+(+1/3)-(+1/12)=0
We get rid of parentheses
-((+1/x))+1/3-1/12=0
We calculate fractions
()/x)*3*12)+12x/x)*3*12)+(-3x)/x)*3*12)=0
We can not solve this equation
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