(1/3)-(19/(4x))=(1/4)-(1/(6x))

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Solution for (1/3)-(19/(4x))=(1/4)-(1/(6x)) equation:


D( x )

6*x = 0

4*x = 0

6*x = 0

6*x = 0

6*x = 0 // : 6

x = 0

4*x = 0

4*x = 0

4*x = 0 // : 4

x = 0

x in (-oo:0) U (0:+oo)

1/3-(19/(4*x)) = 1/4-(1/(6*x)) // - 1/4-(1/(6*x))

1/(6*x)-(19/(4*x))+1/3-(1/4) = 0

(-19/4)*x^-1+1/(6*x)+1/3-1/4 = 0

-55/12*x^-1 = -1/12 // : -55/12

x^-1 = 1/55

-1 < 0

1/(x^1) = 1/55 // * x^1

1 = 1/55*x^1 // : 1/55

55 = x^1

x = 55

x = 55

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