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(1/3)-2b=3
We move all terms to the left:
(1/3)-2b-(3)=0
determiningTheFunctionDomain -2b-3+(1/3)=0
We add all the numbers together, and all the variables
-2b-3+(+1/3)=0
We get rid of parentheses
-2b-3+1/3=0
We multiply all the terms by the denominator
-2b*3+1-3*3=0
We add all the numbers together, and all the variables
-2b*3-8=0
Wy multiply elements
-6b-8=0
We move all terms containing b to the left, all other terms to the right
-6b=8
b=8/-6
b=-1+1/3
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