(1/3)b-2=6-(1/2)b

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Solution for (1/3)b-2=6-(1/2)b equation:



(1/3)b-2=6-(1/2)b
We move all terms to the left:
(1/3)b-2-(6-(1/2)b)=0
Domain of the equation: 3)b!=0
b!=0/1
b!=0
b∈R
Domain of the equation: 2)b)!=0
b!=0/1
b!=0
b∈R
We add all the numbers together, and all the variables
(+1/3)b-(6-(+1/2)b)-2=0
We multiply parentheses
b^2-(6-(+1/2)b)-2=0
We multiply all the terms by the denominator
b^2*2)b)-(6-(-2*2)b)+1=0
We add all the numbers together, and all the variables
b^2*2)b)-(6-(-4)b)+1=0
Wy multiply elements
2b^3-4)b)+1=0
We do not support ebpression: b^3

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