(1/3)k+1=(1/4)k-2

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Solution for (1/3)k+1=(1/4)k-2 equation:



(1/3)k+1=(1/4)k-2
We move all terms to the left:
(1/3)k+1-((1/4)k-2)=0
Domain of the equation: 3)k!=0
k!=0/1
k!=0
k∈R
Domain of the equation: 4)k-2)!=0
k!=0/1
k!=0
k∈R
We add all the numbers together, and all the variables
(+1/3)k-((+1/4)k-2)+1=0
We multiply parentheses
k^2-((+1/4)k-2)+1=0
We multiply all the terms by the denominator
k^2*4)k-2)-((+1*4)k-2)+1=0
We add all the numbers together, and all the variables
k^2*4)k-2)-(4k-2)+1=0
Wy multiply elements
4k^3=0
We do not support ekpression: k^3

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