(1/3)k+80=(1/2)k+120

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Solution for (1/3)k+80=(1/2)k+120 equation:



(1/3)k+80=(1/2)k+120
We move all terms to the left:
(1/3)k+80-((1/2)k+120)=0
Domain of the equation: 3)k!=0
k!=0/1
k!=0
k∈R
Domain of the equation: 2)k+120)!=0
k!=0/1
k!=0
k∈R
We add all the numbers together, and all the variables
(+1/3)k-((+1/2)k+120)+80=0
We multiply parentheses
k^2-((+1/2)k+120)+80=0
We multiply all the terms by the denominator
k^2*2)k+120)-((+80*2)k+120)+1=0
We add all the numbers together, and all the variables
k^2*2)k+120)-(160k+120)+1=0
Wy multiply elements
2k^3=0
We do not support ekpression: k^3

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