(1/3)k-(k+1/4)=(1/12)(k+4)

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Solution for (1/3)k-(k+1/4)=(1/12)(k+4) equation: 


k in (-oo:+oo)

(1/3)*k-k-(1/4) = (1/12)*(k+4) // - (1/12)*(k+4)

(1/3)*k-((1/12)*(k+4))-k-(1/4) = 0

(-1/12)*(k+4)+(1/3)*k-k-1/4 = 0

k/3-1/12*(k+4)-k-1/4 = 0

(-1/12*3*4*(k+4))/(3*4)+(4*k)/(3*4)+(3*4*(-k))/(3*4)+(-1*3)/(3*4) = 0

4*k-1/12*3*4*(k+4)+3*4*(-k)-1*3 = 0

3*k-12*k-4-3 = 0

-9*k-4-3 = 0

-9*k-7 = 0

(-9*k-7)/(3*4) = 0

(-9*k-7)/(3*4) = 0 // * 3*4

-9*k-7 = 0

-9*k-7 = 0 // + 7

-9*k = 7 // : -9

k = 7/(-9)

k = -7/9

k = -7/9

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