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(1/3)p-3=144
We move all terms to the left:
(1/3)p-3-(144)=0
Domain of the equation: 3)p!=0We add all the numbers together, and all the variables
p!=0/1
p!=0
p∈R
(+1/3)p-3-144=0
We add all the numbers together, and all the variables
(+1/3)p-147=0
We multiply parentheses
p^2-147=0
a = 1; b = 0; c = -147;
Δ = b2-4ac
Δ = 02-4·1·(-147)
Δ = 588
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{588}=\sqrt{196*3}=\sqrt{196}*\sqrt{3}=14\sqrt{3}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-14\sqrt{3}}{2*1}=\frac{0-14\sqrt{3}}{2} =-\frac{14\sqrt{3}}{2} =-7\sqrt{3} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+14\sqrt{3}}{2*1}=\frac{0+14\sqrt{3}}{2} =\frac{14\sqrt{3}}{2} =7\sqrt{3} $
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