(1/3)x+(1/2)=-1((4/5)x-2)

Solution for (1/3)x+(1/2)=-1((4/5)x-2) equation:

(1/3)x+(1/2)=-1((4/5)x-2)

We move all terms to the left:

(1/3)x+(1/2)-(-1((4/5)x-2))=0


Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R



Domain of the equation: 5)x-2))!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+1/3)x-(-1((+4/5)x-2))+(+1/2)=0

We multiply parentheses

x^2-(-1((+4/5)x-2))+(+1/2)=0

We get rid of parentheses

x^2-(-1((+4/5)x-2))+1/2=0

We calculate fractions


x^2+()/5x-2))*2)+5x/5x-2))*2)=0

We calculate fractions


x^2+(()*5x)/25x^2+(-2))*2)+5x*5x)/25x^2=0

We multiply all the terms by the denominator


x^2*25x^2+(()*5x)+(-2))*2)+5x*5x)=0


We calculate terms in parentheses: +(()*5x), so:

()*5x


Wy multiply elements

25x^4+(()*5x)+(-2))*2)+5x*5x)=0

We get rid of parentheses

25x^4+(()*5x)-2))*2)+5x*5x=0


We calculate terms in parentheses: +(()*5x), so:

()*5x


We do not support expression: x^4