(1/3)x+12=3x-3

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Solution for (1/3)x+12=3x-3 equation: 



(1/3)x+12=3x-3

We move all terms to the left:

(1/3)x+12-(3x-3)=0



Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/3)x-(3x-3)+12=0

We multiply parentheses

x^2-(3x-3)+12=0

We get rid of parentheses

x^2-3x+3+12=0

We add all the numbers together, and all the variables

x^2-3x+15=0

a = 1; b = -3; c = +15;
Δ = b2-4ac
Δ = -32-4·1·15
Δ = -51
Delta is less than zero, so there is no solution for the equation

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