(1/3)x+2=23

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Solution for (1/3)x+2=23 equation:



(1/3)x+2=23
We move all terms to the left:
(1/3)x+2-(23)=0
Domain of the equation: 3)x!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
(+1/3)x+2-23=0
We add all the numbers together, and all the variables
(+1/3)x-21=0
We multiply parentheses
x^2-21=0
a = 1; b = 0; c = -21;
Δ = b2-4ac
Δ = 02-4·1·(-21)
Δ = 84
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{84}=\sqrt{4*21}=\sqrt{4}*\sqrt{21}=2\sqrt{21}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{21}}{2*1}=\frac{0-2\sqrt{21}}{2} =-\frac{2\sqrt{21}}{2} =-\sqrt{21} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{21}}{2*1}=\frac{0+2\sqrt{21}}{2} =\frac{2\sqrt{21}}{2} =\sqrt{21} $

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