(1/3)x+2=x-4

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Solution for (1/3)x+2=x-4 equation: 



(1/3)x+2=x-4

We move all terms to the left:

(1/3)x+2-(x-4)=0



Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/3)x-(x-4)+2=0

We multiply parentheses

x^2-(x-4)+2=0

We get rid of parentheses

x^2-x+4+2=0

We add all the numbers together, and all the variables

x^2-1x+6=0

a = 1; b = -1; c = +6;
Δ = b2-4ac
Δ = -12-4·1·6
Δ = -23
Delta is less than zero, so there is no solution for the equation

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