(1/3)y+3=(1/7)y

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Solution for (1/3)y+3=(1/7)y equation:



(1/3)y+3=(1/7)y
We move all terms to the left:
(1/3)y+3-((1/7)y)=0
Domain of the equation: 3)y!=0
y!=0/1
y!=0
y∈R
Domain of the equation: 7)y)!=0
y!=0/1
y!=0
y∈R
We add all the numbers together, and all the variables
(+1/3)y-((+1/7)y)+3=0
We multiply parentheses
y^2-((+1/7)y)+3=0
We multiply all the terms by the denominator
y^2*7)y)-((+3*7)y)+1=0
We add all the numbers together, and all the variables
y^2*7)y)-(21y)+1=0
We add all the numbers together, and all the variables
y^2*7)y)-21y+1=0
Wy multiply elements
7y^3=0
We do not support eypression: y^3

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