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(1/3)y+7=(3)y-1
We move all terms to the left:
(1/3)y+7-((3)y-1)=0
Domain of the equation: 3)y!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
(+1/3)y-(3y-1)+7=0
We multiply parentheses
y^2-(3y-1)+7=0
We get rid of parentheses
y^2-3y+1+7=0
We add all the numbers together, and all the variables
y^2-3y+8=0
a = 1; b = -3; c = +8;
Δ = b2-4ac
Δ = -32-4·1·8
Δ = -23
Delta is less than zero, so there is no solution for the equation
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