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(1/3)y-23000=0
Domain of the equation: 3)y!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
(+1/3)y-23000=0
We multiply parentheses
y^2-23000=0
a = 1; b = 0; c = -23000;
Δ = b2-4ac
Δ = 02-4·1·(-23000)
Δ = 92000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{92000}=\sqrt{400*230}=\sqrt{400}*\sqrt{230}=20\sqrt{230}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{230}}{2*1}=\frac{0-20\sqrt{230}}{2} =-\frac{20\sqrt{230}}{2} =-10\sqrt{230} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{230}}{2*1}=\frac{0+20\sqrt{230}}{2} =\frac{20\sqrt{230}}{2} =10\sqrt{230} $
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