(1/36)-(1/40)=(1/t)

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Solution for (1/36)-(1/40)=(1/t) equation:


D( t )

t = 0

t = 0

t = 0

t in (-oo:0) U (0:+oo)

1/36-(1/40) = 1/t // - 1/t

1/36-(1/t)-(1/40) = 0

1/36-t^-1-1/40 = 0

-1*t^-1 = -1/360 // : -1

t^-1 = 1/360

-1 < 0

1/(t^1) = 1/360 // * t^1

1 = 1/360*t^1 // : 1/360

360 = t^1

t = 360

t = 360

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