(1/3b+8)=(1/2b-4)

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Solution for (1/3b+8)=(1/2b-4) equation: 



(1/3b+8)=(1/2b-4)

We move all terms to the left:

(1/3b+8)-((1/2b-4))=0



Domain of the equation: 3b+8)!=0

b∈R





Domain of the equation: 2b-4))!=0

b∈R



We get rid of parentheses

1/3b-((1/2b-4))+8=0

We calculate fractions


2b/6b^2+(-((1*3b)/6b^2+8=0

We add all the numbers together, and all the variables

2b/6b^2+(-((+1*3b)/6b^2+8=0

We calculate fractions

We do not support ebpression: b^4

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