(1/3x)+((6x-9)/3x)=(3x-3)/4x

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Solution for (1/3x)+((6x-9)/3x)=(3x-3)/4x equation:


x in (-oo:+oo)

x*((6*x-9)/3)+(1/3)*x = x*((3*x-3)/4) // - x*((3*x-3)/4)

x*((6*x-9)/3)-(x*((3*x-3)/4))+(1/3)*x = 0

(x*(6*x-9))/3+(-1*x*(3*x-3))/4+x/3 = 0

(4*x*(6*x-9))/(3*4)+(-1*3*x*(3*x-3))/(3*4)+(4*x)/(3*4) = 0

4*x*(6*x-9)-1*3*x*(3*x-3)+4*x = 0

15*x^2-27*x+4*x = 0

15*x^2-23*x = 0

15*x^2-23*x = 0

x*(15*x-23) = 0

15*x-23 = 0 // + 23

15*x = 23 // : 15

x = 23/15

x*(x-23/15) = 0

(x*(x-23/15))/(3*4) = 0

(x*(x-23/15))/(3*4) = 0 // * 3*4

x*(x-23/15) = 0

( x-23/15 )

x-23/15 = 0 // + 23/15

x = 23/15

( x )

x = 0

x in { 23/15, 0 }

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