(1/3x)+3=4-x

Solution for (1/3x)+3=4-x equation:

(1/3x)+3=4-x

We move all terms to the left:

(1/3x)+3-(4-x)=0


Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+1/3x)-(-1x+4)+3=0

We get rid of parentheses

1/3x+1x-4+3=0

We multiply all the terms by the denominator


1x*3x-4*3x+3*3x+1=0

Wy multiply elements

3x^2-12x+9x+1=0

We add all the numbers together, and all the variables

3x^2-3x+1=0

a = 3; b = -3; c = +1;
Δ = b2-4ac
Δ = -32-4·3·1
Δ = -3
Delta is less than zero, so there is no solution for the equation