(1/3x)+6=12

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Solution for (1/3x)+6=12 equation: 



(1/3x)+6=12

We move all terms to the left:

(1/3x)+6-(12)=0



Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/3x)+6-12=0

We add all the numbers together, and all the variables

(+1/3x)-6=0

We get rid of parentheses

1/3x-6=0

We multiply all the terms by the denominator


-6*3x+1=0

Wy multiply elements

-18x+1=0

We move all terms containing x to the left, all other terms to the right

-18x=-1

x=-1/-18

x=1/18

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