(1/3x)-2=(1/6)+1

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Solution for (1/3x)-2=(1/6)+1 equation: 



(1/3x)-2=(1/6)+1

We move all terms to the left:

(1/3x)-2-((1/6)+1)=0



Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/3x)-2-((+1/6)+1)=0

We get rid of parentheses

1/3x-2-((+1/6)+1)=0

We calculate fractions


()/18x^2+(-((+1*3x)/18x^2-2=0

We calculate fractions

We do not support expression: x^4

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