(1/3x+5)=(1/3x+-5)

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Solution for (1/3x+5)=(1/3x+-5) equation: 



(1/3x+5)=(1/3x+-5)

We move all terms to the left:

(1/3x+5)-((1/3x+-5))=0



Domain of the equation: 3x+5)!=0

x∈R





Domain of the equation: 3x+-5))!=0

x∈R



We add all the numbers together, and all the variables

(1/3x+5)-((1/3x-5))=0

We get rid of parentheses

1/3x-((1/3x-5))+5=0

We calculate fractions


3x/9x^2+(-((1*3x)/9x^2+5=0

We add all the numbers together, and all the variables

3x/9x^2+(-((+1*3x)/9x^2+5=0

We calculate fractions

We do not support expression: x^4

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