(1/3x+8)=(3/4x-18)=(1/2x)

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Solution for (1/3x+8)=(3/4x-18)=(1/2x) equation: 



(1/3x+8)=(3/4x-18)=(1/2x)

We move all terms to the left:

(1/3x+8)-((3/4x-18))=0



Domain of the equation: 3x+8)!=0

x∈R





Domain of the equation: 4x-18))!=0

x∈R



We get rid of parentheses

1/3x-((3/4x-18))+8=0

We calculate fractions


4x/12x^2+(-((3*3x)/12x^2+8=0

We add all the numbers together, and all the variables

4x/12x^2+(-((+3*3x)/12x^2+8=0

We calculate fractions

We do not support expression: x^4

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