(1/3x-6)-(5/x-2)=12

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Solution for (1/3x-6)-(5/x-2)=12 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(1/3)*x-(5/x)-6+2 = 12 // - 12

(1/3)*x-(5/x)-12-6+2 = 0

(1/3)*x-5*x^-1-12-6+2 = 0

1/3*x^1-5*x^-1-16*x^0 = 0

(1/3*x^2-16*x^1-5*x^0)/(x^1) = 0 // * x^2

x^1*(1/3*x^2-16*x^1-5*x^0) = 0

x^1

(1/3)*x^2-16*x-5 = 0

(1/3)*x^2-16*x-5 = 0

DELTA = (-16)^2-(-5*4*(1/3))

DELTA = 788/3

DELTA > 0

x = ((788/3)^(1/2)+16)/(2*(1/3)) or x = (16-(788/3)^(1/2))/(2*(1/3))

x = 3/2*((788/3)^(1/2)+16) or x = 3/2*(16-(788/3)^(1/2))

x in { 3/2*(16-(788/3)^(1/2)), 3/2*((788/3)^(1/2)+16)}

x in { 3/2*(16-(788/3)^(1/2)), 3/2*((788/3)^(1/2)+16) }

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