(1/4)(2(x-1)+10)=x

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Solution for (1/4)(2(x-1)+10)=x equation:



(1/4)(2(x-1)+10)=x
We move all terms to the left:
(1/4)(2(x-1)+10)-(x)=0
Domain of the equation: 4)(2(x-1)+10)!=0
x∈R
We add all the numbers together, and all the variables
(+1/4)(2(x-1)+10)-x=0
We add all the numbers together, and all the variables
-1x+(+1/4)(2(x-1)+10)=0
We multiply all the terms by the denominator
-1x*4)(2(x-1)+1+10)+(=0
We add all the numbers together, and all the variables
-1x*4)(2(x-1)=0
Wy multiply elements
-4x^2=0
a = -4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-4)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-8}=0$

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