(1/4)(28-4h)=7-h

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Solution for (1/4)(28-4h)=7-h equation: 


h in (-oo:+oo)

(1/4)*(28-(4*h)) = 7-h // - 7-h

(1/4)*(28-(4*h))+h-7 = 0

(1/4)*(28-4*h)+h-7 = 0

1/4*(28-4*h)+h-7 = 0

1/4*(28-4*h)+h-7 = 0

7-7 = 0

0 = 0

0 = 0

h belongs to the empty set

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