(1/4)(6+13x)=(1/3)(7x-1)

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Solution for (1/4)(6+13x)=(1/3)(7x-1) equation: 



(1/4)(6+13x)=(1/3)(7x-1)

We move all terms to the left:

(1/4)(6+13x)-((1/3)(7x-1))=0



Domain of the equation: 4)(6+13x)!=0

x∈R





Domain of the equation: 3)(7x-1))!=0

x∈R



We add all the numbers together, and all the variables

(+1/4)(13x+6)-((+1/3)(7x-1))=0

We multiply parentheses ..

(+13x^2+1/4*6)-((+1/3)(7x-1))=0

We calculate fractions


((+13x^2+1*3)(7x-1)))/72x^2+()/72x^2=0

We can not solve this equation

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