(1/4)(k-1)=10

Solution for (1/4)(k-1)=10 equation:

(1/4)(k-1)=10

We move all terms to the left:

(1/4)(k-1)-(10)=0


Domain of the equation: 4)(k-1)!=0

k∈R


We add all the numbers together, and all the variables

(+1/4)(k-1)-10=0

We multiply parentheses ..

(+k^2+1/4*-1)-10=0

We multiply all the terms by the denominator


(+k^2+1-10*4*-1)=0

We get rid of parentheses

k^2+1-1-10*4*=0

We add all the numbers together, and all the variables

k^2=0

a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$k=\frac{-b}{2a}=\frac{0}{2}=0$