(1/4)(m-12)=(-3/4)m+3

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Solution for (1/4)(m-12)=(-3/4)m+3 equation:



(1/4)(m-12)=(-3/4)m+3
We move all terms to the left:
(1/4)(m-12)-((-3/4)m+3)=0
Domain of the equation: 4)(m-12)!=0
m∈R
Domain of the equation: 4)m+3)!=0
m!=0/1
m!=0
m∈R
We add all the numbers together, and all the variables
(+1/4)(m-12)-((-3/4)m+3)=0
We multiply parentheses ..
(+m^2+1/4*-12)-((-3/4)m+3)=0
We calculate fractions
We do not support empression: m^3

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