(1/4)(r-16)=7

Solution for (1/4)(r-16)=7 equation:

(1/4)(r-16)=7

We move all terms to the left:

(1/4)(r-16)-(7)=0


Domain of the equation: 4)(r-16)!=0

r∈R


We add all the numbers together, and all the variables

(+1/4)(r-16)-7=0

We multiply parentheses ..

(+r^2+1/4*-16)-7=0

We multiply all the terms by the denominator


(+r^2+1-7*4*-16)=0

We get rid of parentheses

r^2+1-16-7*4*=0

We add all the numbers together, and all the variables

r^2=0

a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$r=\frac{-b}{2a}=\frac{0}{2}=0$