(1/4)(x+3)=4(x+3)

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Solution for (1/4)(x+3)=4(x+3) equation: 



(1/4)(x+3)=4(x+3)

We move all terms to the left:

(1/4)(x+3)-(4(x+3))=0



Domain of the equation: 4)(x+3)!=0

x∈R



We add all the numbers together, and all the variables

(+1/4)(x+3)-(4(x+3))=0

We multiply parentheses ..

(+x^2+1/4*3)-(4(x+3))=0

We multiply all the terms by the denominator


(+x^2+1-((4(x+3)))*4*3)=0



We calculate terms in parentheses: +(+x^2+1-((4(x+3)))*4*3), so:

+x^2+1-((4(x+3)))*4*3

determiningTheFunctionDomain
x^2-((4(x+3)))*4*3+1

Back to the equation:

+(x^2-((4(x+3)))*4*3+1)





We calculate terms in parentheses: +(x^2-((4(x+3)))*4*3+1), so:

x^2-((4(x+3)))*4*3+1





We calculate terms in parentheses: +(x^2-((4(x+3)))*4*3+1), so:

x^2-((4(x+3)))*4*3+1





We calculate terms in parentheses: +(x^2-((4(x+3)))*4*3+1), so:

x^2-((4(x+3)))*4*3+1





We calculate terms in parentheses: +(x^2-((4(x+3)))*4*3+1), so:

x^2-((4(x+3)))*4*3+1





We calculate terms in parentheses: +(x^2-((4(x+3)))*4*3+1), so:

x^2-((4(x+3)))*4*3+1





We calculate terms in parentheses: +(x^2-((4(x+3)))*4*3+1), so:

x^2-((4(x+3)))*4*3+1





We calculate terms in parentheses: +(x^2-((4(x+3)))*4*3+1), so:

x^2-((4(x+3)))*4*3+1





We calculate terms in parentheses: +(x^2-((4(x+3)))*4*3+1), so:

x^2-((4(x+3)))*4*3+1





We calculate terms in parentheses: +(x^2-((4(x+3)))*4*3+1), so:

x^2-((4(x+3)))*4*3+1





We calculate terms in parentheses: +(x^2-((4(x+3)))*4*3+1), so:

x^2-((4(x+3)))*4*3+1





We calculate terms in parentheses: +(x^2-((4(x+3)))*4*3+1), so:

x^2-((4(x+3)))*4*3+1





We calculate terms in parentheses: +(x^2-((4(x+3)))*4*3+1), so:

x^2-((4(x+3)))*4*3+1





We calculate terms in parentheses: +(x^2-((4(x+3)))*4*3+1), so:

x^2-((4(x+3)))*4*3+1





We calculate terms in parentheses: +(x^2-((4(x+3)))*4*3+1), so:

x^2-((4(x+3)))*4*3+1





We calculate terms in parentheses: +(x^2-((4(x+3)))*4*3+1), so:

x^2-((4(x+3)))*4*3+1





We calculate terms in parentheses: +(x^2-((4(x+3)))*4*3+1), so:

x^2-((4(x+3)))*4*3+1





We calculate terms in parentheses: +(x^2-((4(x+3)))*4*3+1), so:

x^2-((4(x+3)))*4*3+1





We calculate terms in parentheses: +(x^2-((4(x+3)))*4*3+1), so:

x^2-((4(x+3)))*4*3+1





We calculate terms in parentheses: +(x^2-((4(x+3)))*4*3+1), so:

x^2-((4(x+3)))*4*3+1





We calculate terms in parentheses: +(x^2-((4(x+3)))*4*3+1), so:

x^2-((4(x+3)))*4*3+1





We calculate terms in parentheses: +(x^2-((4(x+3)))*4*3+1), so:

x^2-((4(x+3)))*4*3+1





We calculate terms in parentheses: +(x^2-((4(x+3)))*4*3+1), so:

x^2-((4(x+3)))*4*3+1





We calculate terms in parentheses: +(x^2-((4(x+3)))*4*3+1), so:

x^2-((4(x+3)))*4*3+1





We calculate terms in parentheses: +(x^2-((4(x+3)))*4*3+1), so:

x^2-((4(x+3)))*4*3+1





We calculate terms in parentheses: +(x^2-((4(x+3)))*4*3+1), so:

x^2-((4(x+3)))*4*3+1





We calculate terms in parentheses: +(x^2-((4(x+3)))*4*3+1), so:

x^2-((4(x+3)))*4*3+1





We calculate terms in parentheses: +(x^2-((4(x+3)))*4*3+1), so:

x^2-((4(x+3)))*4*3+1





We calculate terms in parentheses: +(x^2-((4(x+3)))*4*3+1), so:

x^2-((4(x+3)))*4*3+1





We calculate terms in parentheses: +(x^2-((4(x+3)))*4*3+1), so:

x^2-((4(x+3)))*4*3+1





We calculate terms in parentheses: +(x^2-((4(x+3)))*4*3+1), so:

x^2-((4(x+3)))*4*3+1





We calculate terms in parentheses: +(x^2-((4(x+3)))*4*3+1), so:

x^2-((4(x+3)))*4*3+1





We calculate terms in parentheses: +(x^2-((4(x+3)))*4*3+1), so:

x^2-((4(x+3)))*4*3+1





We calculate terms in parentheses: +(x^2-((4(x+3)))*4*3+1), so:

x^2-((4(x+3)))*4*3+1





We calculate terms in parentheses: +(x^2-((4(x+3)))*4*3+1), so:

x^2-((4(x+3)))*4*3+1





We calculate terms in parentheses: +(x^2-((4(x+3)))*4*3+1), so:

x^2-((4(x+3)))*4*3+1





We calculate terms in parentheses: +(x^2-((4(x+3)))*4*3+1), so:

x^2-((4(x+3)))*4*3+1





We calculate terms in parentheses: +(x^2-((4(x+3)))*4*3+1), so:

x^2-((4(x+3)))*4*3+1





We calculate terms in parentheses: +(x^2-((4(x+3)))*4*3+1), so:

x^2-((4(x+3)))*4*3+1





We calculate terms in parentheses: +(x^2-((4(x+3)))*4*3+1), so:

x^2-((4(x+3)))*4*3+1





							

									
									
									
									
									
									

														
			

			
				

						
				
				
					
			
						
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