(1/4)-(5/4k)=(5/k)

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Solution for (1/4)-(5/4k)=(5/k) equation: 


D( k )

k = 0

k = 0

k = 0

k in (-oo:0) U (0:+oo)

1/4-((5/4)*k) = 5/k // - 5/k

1/4-((5/4)*k)-(5/k) = 0

(-5/4)*k-5*k^-1+1/4 = 0

1/4*k^0-5/4*k^1-5*k^-1 = 0

(1/4*k^1-5/4*k^2-5*k^0)/(k^1) = 0 // * k^2

k^1*(1/4*k^1-5/4*k^2-5*k^0) = 0

k^1

(-5/4)*k^2+(1/4)*k-5 = 0

(-5/4)*k^2+(1/4)*k-5 = 0

DELTA = (1/4)^2-(-5*4*(-5/4))

DELTA = -399/16

DELTA < 0

k in { } 

k belongs to the empty set

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