If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(1/4)c=2+(3/4)
We move all terms to the left:
(1/4)c-(2+(3/4))=0
Domain of the equation: 4)c!=0We add all the numbers together, and all the variables
c!=0/1
c!=0
c∈R
(+1/4)c-(2+(+3/4))=0
We multiply parentheses
c^2-(2+(+3/4))=0
We multiply all the terms by the denominator
c^2*4))-(2+(+3=0
Wy multiply elements
4c^3+3=0
We do not support ecpression: c^3
| C=(92−x)36+(92−40)⋅48 | | 2x-4(x-1)=16+2x | | 5x+36=9x-4 | | 6=2-2x10 | | 9=x−3 | | 6(6-6x)=324 | | {n}{6}+5=4 | | 3x+14+5x=12 | | -29-3n=8-(8n-3) | | 5(x-2)-3=-5(-2x+3)-9 | | -10.3=w/7+7.2 | | 5m=20+3m | | (40+x)36+(92−(40+x))⋅48=C | | 4*(2x+7)=16 | | -h-20=12h+19 | | 50+14x=330 | | 15–5(4x–7)=50 | | 8(x)=110-3(x) | | 6/8x4+2=6 | | 16=10–3m | | 3(4x+9)=-25+4 | | 37=7r-5 | | 8(x-1)=568 | | (40+x)36+(92−(40+x))⋅48=C | | 18-5(x-10)=-7 | | 8x5=5x | | 39−5d=–56 | | 17=7+2p | | x+10x3=x5 | | 5x-6=14+1x | | f/2+11=14 | | 5(3+x)=17 |