(1/4)j-7=9

Solution for (1/4)j-7=9 equation:

(1/4)j-7=9

We move all terms to the left:

(1/4)j-7-(9)=0


Domain of the equation: 4)j!=0

j!=0/1

j!=0

j∈R


We add all the numbers together, and all the variables

(+1/4)j-7-9=0

We add all the numbers together, and all the variables

(+1/4)j-16=0

We multiply parentheses

j^2-16=0

a = 1; b = 0; c = -16;
Δ = b2-4ac
Δ = 02-4·1·(-16)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8}{2*1}=\frac{-8}{2}
=-4
$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8}{2*1}=\frac{8}{2}
=4
$