(1/4)t+(2/5)=(1/5)-t

Solution for (1/4)t+(2/5)=(1/5)-t equation:

(1/4)t+(2/5)=(1/5)-t

We move all terms to the left:

(1/4)t+(2/5)-((1/5)-t)=0


Domain of the equation: 4)t!=0

t!=0/1

t!=0

t∈R



Domain of the equation: 5)-t)!=0

t!=0/1

t!=0

t∈R


We add all the numbers together, and all the variables

(+1/4)t-((+1/5)-t)+(+2/5)=0

We multiply parentheses

t^2-((+1/5)-t)+(+2/5)=0

We get rid of parentheses

t^2-((+1/5)-t)+2/5=0

We calculate fractions


t^2=0

a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{0}{2}=0$