(1/4)x-(x+(1/5))=(1/20)(x+5)

Solution for (1/4)x-(x+(1/5))=(1/20)(x+5) equation:

(1/4)x-(x+(1/5))=(1/20)(x+5)

We move all terms to the left:

(1/4)x-(x+(1/5))-((1/20)(x+5))=0


Domain of the equation: 4)x!=0

x!=0/1

x!=0

x∈R



Domain of the equation: 20)(x+5))!=0

x∈R


We add all the numbers together, and all the variables

(+1/4)x-(x+(+1/5))-((+1/20)(x+5))=0

We multiply parentheses

x^2-(x+(+1/5))-((+1/20)(x+5))=0

We multiply parentheses ..

x^2-((+x^2+1/20*5))-(x+(+1/5))=0

We calculate fractions


x^2+(-1x^2-5)/()+(-1x-100)/()=0

We multiply all the terms by the denominator


(-1x^2-5)+x^2*()+(-1x-100)=0

We get rid of parentheses

-1x^2+x^2*()-1x-5-100=0

We add all the numbers together, and all the variables

-1x^2+x^2*()-1x-105=0

We move all terms containing x to the left, all other terms to the right

-1x^2+x^2*()-1x=105