(1/4)y+12=y+6

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Solution for (1/4)y+12=y+6 equation: 



(1/4)y+12=y+6

We move all terms to the left:

(1/4)y+12-(y+6)=0



Domain of the equation: 4)y!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

(+1/4)y-(y+6)+12=0

We multiply parentheses

y^2-(y+6)+12=0

We get rid of parentheses

y^2-y-6+12=0

We add all the numbers together, and all the variables

y^2-1y+6=0

a = 1; b = -1; c = +6;
Δ = b2-4ac
Δ = -12-4·1·6
Δ = -23
Delta is less than zero, so there is no solution for the equation

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