(1/4)y+6=(1/5)y

Solution for (1/4)y+6=(1/5)y equation:

(1/4)y+6=(1/5)y

We move all terms to the left:

(1/4)y+6-((1/5)y)=0


Domain of the equation: 4)y!=0

y!=0/1

y!=0

y∈R



Domain of the equation: 5)y)!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

(+1/4)y-((+1/5)y)+6=0

We multiply parentheses

y^2-((+1/5)y)+6=0

We multiply all the terms by the denominator


y^2*5)y)-((+6*5)y)+1=0

We add all the numbers together, and all the variables

y^2*5)y)-(30y)+1=0

We add all the numbers together, and all the variables

y^2*5)y)-30y+1=0

Wy multiply elements

5y^3=0

We do not support eypression: y^3