(1/4)z-(2/7)=(5/7)

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Solution for (1/4)z-(2/7)=(5/7) equation: 



(1/4)z-(2/7)=(5/7)

We move all terms to the left:

(1/4)z-(2/7)-((5/7))=0



Domain of the equation: 4)z!=0

z!=0/1

z!=0

z∈R



We add all the numbers together, and all the variables

(+1/4)z-(+2/7)-((+5/7))=0

We multiply parentheses

z^2-(+2/7)-((+5/7))=0

We get rid of parentheses

z^2-2/7-((+5/7))=0

We calculate fractions


z^2=0

a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$z=\frac{-b}{2a}=\frac{0}{2}=0$

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