(1/49)x+1=25/9

Solution for (1/49)x+1=25/9 equation:

(1/49)x+1=25/9

We move all terms to the left:

(1/49)x+1-(25/9)=0


Domain of the equation: 49)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+1/49)x+1-(+25/9)=0

We multiply parentheses

x^2+1-(+25/9)=0

We get rid of parentheses

x^2+1-25/9=0

We multiply all the terms by the denominator


x^2*9-25+1*9=0

We add all the numbers together, and all the variables

x^2*9-16=0

Wy multiply elements

9x^2-16=0

a = 9; b = 0; c = -16;
Δ = b2-4ac
Δ = 02-4·9·(-16)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24}{2*9}=\frac{-24}{18}
=-1+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24}{2*9}=\frac{24}{18}
=1+1/3
$