(1/4x)+(3/8x)=-5

Solution for (1/4x)+(3/8x)=-5 equation:

(1/4x)+(3/8x)=-5

We move all terms to the left:

(1/4x)+(3/8x)-(-5)=0


Domain of the equation: 4x)!=0

x!=0/1

x!=0

x∈R



Domain of the equation: 8x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+1/4x)+(+3/8x)-(-5)=0

We add all the numbers together, and all the variables

(+1/4x)+(+3/8x)+5=0

We get rid of parentheses

1/4x+3/8x+5=0

We calculate fractions


8x/32x^2+12x/32x^2+5=0

We multiply all the terms by the denominator


8x+12x+5*32x^2=0

We add all the numbers together, and all the variables

20x+5*32x^2=0

Wy multiply elements

160x^2+20x=0

a = 160; b = 20; c = 0;
Δ = b2-4ac
Δ = 202-4·160·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-20}{2*160}=\frac{-40}{320}
=-1/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+20}{2*160}=\frac{0}{320}
=0
$