(1/4x)+3=(3/4x)+1;x

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Solution for (1/4x)+3=(3/4x)+1;x equation: 



(1/4x)+3=(3/4x)+1x

We move all terms to the left:

(1/4x)+3-((3/4x)+1x)=0



Domain of the equation: 4x)!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 4x)+1x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/4x)-((+3/4x)+1x)+3=0

We get rid of parentheses

1/4x-((+3/4x)+1x)+3=0

We calculate fractions


4x/16x^2+(-((+3*4x)/16x^2+3=0

We calculate fractions

We do not support expression: x^4

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