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(1/4x+2)=(2/5x-1)
We move all terms to the left:
(1/4x+2)-((2/5x-1))=0
Domain of the equation: 4x+2)!=0
x∈R
Domain of the equation: 5x-1))!=0We get rid of parentheses
x∈R
1/4x-((2/5x-1))+2=0
We calculate fractions
5x/20x^2+(-((2*4x)/20x^2+2=0
We add all the numbers together, and all the variables
5x/20x^2+(-((+2*4x)/20x^2+2=0
We calculate fractions
We do not support expression: x^4
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