(1/5)(20x+30)=(1/3)(6x+36)

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Solution for (1/5)(20x+30)=(1/3)(6x+36) equation: 



(1/5)(20x+30)=(1/3)(6x+36)

We move all terms to the left:

(1/5)(20x+30)-((1/3)(6x+36))=0



Domain of the equation: 5)(20x+30)!=0

x∈R





Domain of the equation: 3)(6x+36))!=0

x∈R



We add all the numbers together, and all the variables

(+1/5)(20x+30)-((+1/3)(6x+36))=0

We multiply parentheses ..

(+20x^2+1/5*30)-((+1/3)(6x+36))=0

We calculate fractions


((+20x^2+1*3)(6x+36)))/450x^2+()/450x^2=0

We can not solve this equation

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