(1/5)(20x+30)=(1/3)(6x+36)

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Solution for (1/5)(20x+30)=(1/3)(6x+36) equation:



(1/5)(20x+30)=(1/3)(6x+36)
We move all terms to the left:
(1/5)(20x+30)-((1/3)(6x+36))=0
Domain of the equation: 5)(20x+30)!=0
x∈R
Domain of the equation: 3)(6x+36))!=0
x∈R
We add all the numbers together, and all the variables
(+1/5)(20x+30)-((+1/3)(6x+36))=0
We multiply parentheses ..
(+20x^2+1/5*30)-((+1/3)(6x+36))=0
We calculate fractions
((+20x^2+1*3)(6x+36)))/450x^2+()/450x^2=0
We can not solve this equation

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