If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x in (-oo:+oo)
(1/5)*(35*y+30*y+35*z) = 0
1/5*(65*y+35*z) = 0
x belongs to the empty set
| 2x^2+21x+40= | | 10-5(2x+4y)= | | -7+5x=3x-3 | | 1x+.5=0 | | 12/5(10/3b+15/4) | | 9-x=6x-33 | | 6a^3-4ab+2a^3= | | x+2=-34-2x | | 1/4x^2-x+1/2=0 | | 3(5y+6z)-18z= | | 6x/15=400 | | -.5=.663 | | 4y(7y-6)+18y= | | 4(5x+3)=4x+30 | | 3(2n+1)=51 | | 28x^2-19xy+3y^2= | | 8x^5-16x^4-10x^3=0 | | x-4=23 | | 4(6x+4)-3= | | -3x+5y+(2y+5x)= | | 9x^2y-25y^2=225 | | y=9-8x | | 4x-7=43+8(x-2) | | 2/x=-65 | | 5y-4-2y+2=0 | | a^5-12ab+8a^5= | | (x+9)(x-5)=(x+1)2 | | 4y-4-2y+2=0 | | 150/6 | | 6x-7=21x+3 | | 9+5q=10+4q | | 12x-6=10x |